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Jul - General Chat - A new revolution in math! New poll - New thread - New reply
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Drag
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Posted on 01-31-11 09:23:52 PM Link | Quote
1953
I discovered the end of the numbers. Basically, a number that is so big, there are no other numbers that are bigger than it. Let's call it J. Conversely, -J is the smallest possible number.

J + 1 = J
J - 1 = J - 1

-J + 1 = -J + 1
-J - 1 = -J

nJ = J
J/n = J/n

J^n = J
J^(1/n) = J^(1/n)

When you think about it, J is a lot better than infinity:
f(x) = x^2
g(x) = x^3

When x = infinity, f(x) != g(x) even though they both evaluate to "infinity".

However, when x = J, f(x) == g(x), because they both evaluate to J. Less confusing!

There is still some debate as to whether J + 1 = -J, and -J - 1 = J, but J + 1 = J is the commonly accepted behavior.

So yeah, suck on that, Pythagoras.

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Posted on 01-31-11 09:30:58 PM Link | Quote
And I thought you discovered how to properly divide by zero.

You disappointed me.

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Posted on 01-31-11 09:31:45 PM Link | Quote
Cirvy is gonna have fun with this when he shows up.

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Sine
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Posted on 01-31-11 09:32:13 PM Link | Quote
It's an enigma
----------------------------------------------------
Originally posted by Teyla
Cirvy is gonna have fun with this when he shows up.
Beating him to it.

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devin

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Posted on 01-31-11 09:34:49 PM Link | Quote
Originally posted by Drag

When you think about it, J is a lot better than infinity



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misterj
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Posted on 01-31-11 09:37:10 PM Link | Quote
I am a fan of this theory for personal reasons.

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Drag
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Posted on 01-31-11 09:37:50 PM Link | Quote
1954
Originally posted by devin
Originally posted by Drag

When you think about it, J is a lot better than infinity



Even primitive alphabet machines have a key for J. Let's see you type a sideways-8 on a Speak&Spell.

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Posted on 01-31-11 09:38:57 PM Link | Quote

Isn't that like IEEE floating-point inf, then? Or am I missing something?

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Sine
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Posted on 01-31-11 09:43:28 PM Link | Quote
It's an enigma
----------------------------------------------------
Just as a side note

J + 1 = J

J + (-J) + 1 = J + (-J)

1 = 0

I mean really?

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Drag
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Posted on 01-31-11 09:46:41 PM Link | Quote
1955
Originally posted by Imajin
Isn't that like IEEE floating-point inf, then? Or am I missing something?

Nah, I think you've got it. In the computing world, there is a such thing as a number that's too big to have any bigger numbers than it, and the same thing for small numbers. In the end though, the IEEE floating-point infinity ends up being finite, so you could classify it as J.

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Drag
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Posted on 01-31-11 09:48:55 PM (last edited by Drag at 01-31-11 06:51 PM) Link | Quote
1956
Originally posted by Sine
Just as a side note

J + 1 = J

J + (-J) + 1 = J + (-J)

1 = 0

I mean really?


J + 1 = J --> J = J

Thus,

J + (-J) + 1 = J + (-J)

J + (-J) = J + (-J)

0 = 0


You wouldn't say 3 * 2 + 1 = 3 * 2 + 1 --> 7 = 9, would you?

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misterj
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Posted on 01-31-11 09:51:41 PM Link | Quote
Hello Drag, welcome to Jul. Please do not double post. Be sure to read the FAQ as well. Have a nice stay!

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Sine
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Posted on 01-31-11 09:51:59 PM (last edited by Sine at 01-31-11 06:52 PM) Link | Quote
It's an enigma
----------------------------------------------------
Originally posted by Drag
You wouldn't say 3 * 2 + 1 = 3 * 2 + 1 --> 7 = 9, would you?
No, because (3*2) + 1 != 3 * (2+1). If you're obeying normal number laws, you'd recognize that J must be commutative with normal numbers over the same operations.

Thus my logic still stands.

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Drag
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Posted on 01-31-11 10:05:23 PM Link | Quote
1957
Originally posted by Sine
If you're obeying normal number laws, you'd recognize that J must be commutative with normal numbers over the same operations.


J needs to be evaluated before anything else is evaluated, save for maybe things in parenthesis.

J + (-J) + 1

The 1 gets cancelled out before the Js cancel each other out. I'd need to do a little more research, but the order of operations would likely be changed like PJEMDAS, or something similar.

Thus, if you adhere to the proper rules of J:

J + (-J) + 1 = J + (-J)
0 = 0

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Posted on 01-31-11 10:08:19 PM (last edited by misterj at 01-31-11 07:08 PM) Link | Quote
-- YOU HAVE JUST BEEN OWNED BY DRAG. SEEK MEDICAL ATTENTION IMMEDIATELY. TREAT FOR SHOCK AND KEEP EXTREMITIES ELEVATED. DO NOT MOVE ANY OF YOUR JOINTS UNTIL MEDICAL ATTENTION ARRIVES. TRY TO STAY OFF YOUR FEET FOR 4-6 WEEKS AFTERWARD. YOU HAVE JUST BEEN OWNED BY DRAG --

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Posted on 01-31-11 10:34:19 PM Link | Quote
-J wouldn't be the smallest number, since making a number negative doesn't reduce its size. It just means it's of the greatest scalar magnitude in the negative direction.

The smallest number is zero.

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Posted on 01-31-11 10:42:47 PM Link | Quote
? / 0 is just "undefined". It isn't possible to do.

I don't see why everyone makes it out to be a big deal.

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Sine
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Posted on 01-31-11 10:45:32 PM Link | Quote
It's an enigma
----------------------------------------------------
Originally posted by Gig
? / 0 is just "undefined". It isn't possible to do.

I don't see why everyone makes it out to be a big deal.
In certain algebraic rings it's defined.

But we're not going to talk about those here

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Posted on 01-31-11 10:46:49 PM Link | Quote
Originally posted by Sine
Originally posted by Gig
? / 0 is just "undefined". It isn't possible to do.

I don't see why everyone makes it out to be a big deal.
In certain algebraic rings it's defined.

But we're not going to talk about those here

I mean in basic math. Just like -11/2 isn't possible until you start figuring in imaginary numbers.

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Posted on 01-31-11 10:51:52 PM Link | Quote

Originally posted by Gig
? / 0 is just "undefined". It isn't possible to do.

I don't see why everyone makes it out to be a big deal.

People don't like being told they can't do things.

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