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05-03-22 12:12:59 AM
Jul - General Chat - In a three-dimensional space with no gravity, how would you define falling? New poll - New thread - New reply
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Posted on 09-11-09 03:54:13 AM Link | Quote

Hydra: Any momentum given off when an object is placed in said 3D no grav. area? Because when watching it, one could determine a fall, but it wouldn't be a 'true fall.'

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Posted on 09-11-09 03:55:36 AM Link | Quote





IMO, with the platform, falling would be going under one side, while flying/levitating would be going above the other side.

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Posted on 09-11-09 04:07:31 AM Link | Quote
Well, if the platform is a cube, it's hard to define the individual sides.

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Posted on 09-11-09 10:39:28 AM Link | Quote
Depending on the mass of the platform itself, you may very well generate a bigger gravitational pull. So would the platform fall towards you?
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Posted on 09-11-09 10:43:32 AM Link | Quote
I would define it as "whatever direction is in the direction of looking downwards".

This assumes that "up" is above your head and down is below your feet. i.e., travelling in the direction your legs are pointing would be falling, and the opposite is rising.

Reason being that for the most part, we fall feet-down (or try to right ourselves to be as such). Without gravity to tell, you just go from what you know; feet is down, head is up.

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Posted on 09-11-09 06:23:00 PM Link | Quote
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Downwards in microgravity would basically be either A) The vector extending from my head through my feet, B) whatever's left of the floor in the event someone just removered most of what I'm standing on, or C) the planet I'm in orbit above.

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Posted on 09-12-09 05:33:19 AM Link | Quote




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With no gravity, I wouldn't define falling.

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Jul - General Chat - In a three-dimensional space with no gravity, how would you define falling? New poll - New thread - New reply


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